230 LED Circuit
You will need to connect another silicond diode (1N4004 or similar) to protect LED against reversed polarity.
If you assume that your LED current will be 10mA then to drop 220V you need approximately 22000Ω.
As suggested by mrcube_ns you can use a capacitor (no heat) instead of a resistor.
So here are data necessary to performe calculations:
Rc(for 10mA @220V) = 22000Ω
ω=2 *Π * f
f=50Hz
C = 1/ωRc=1/2*Π*50*22000=144nF closesed available capacitor 150nF/400V…
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Thanks
very good ckt. for me.
because i search very long time this ckt
Hi.. what abt Heat? is it producing high heat? what abt this circuit life? can i connect one or two bright led??
how to use 50 nos leds in 230v ac ineed it urgently pls help me